(3y+2)(y-6)=3y^2

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Solution for (3y+2)(y-6)=3y^2 equation: 



(3y+2)(y-6)=3y^2

We move all terms to the left:

(3y+2)(y-6)-(3y^2)=0

determiningTheFunctionDomain
-3y^2+(3y+2)(y-6)=0

We multiply parentheses ..

-3y^2+(+3y^2-18y+2y-12)=0

We get rid of parentheses

-3y^2+3y^2-18y+2y-12=0

We add all the numbers together, and all the variables

-16y-12=0

We move all terms containing y to the left, all other terms to the right

-16y=12

y=12/-16

y=-3/4

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